abcd is a quadtrilateral in which all the four angles are equal. show that ab ii cd and ad ii bc
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Proof
∡ A+∡B+∡Ç+∡D=360° [sum of the angles of a quadtrilateral=360° ]
=>∡A+∡A+∡A+∡A=360°
=>4*∡A=360°
=>∡A=90°
Again, ∡ A+∡B=180°
Therefore, ∡ A and ∡B are supplementary angle
so they are adjacent angles
∴ AD || BC [∵ there interior ∡ A +∡ B =180°.]
Similarly, angle∡A+∡D=180°
∴, angles ∡A and ∡D supplementary angle
so they are adjacent ∡
∴ AB || CD [∵ there interior angles ∡A + ∡B = 180°.]∵
hence it is proved that AB ||CD
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