ABCD is a rectangle ABCD 2 11 cm BC is equal to 60 cm find AC
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Answered by
1
ABCD is a rectangle AB = 11cm, BC=60cm then find AC
(I think this is your question)
In ∆ABC, <ABC=90°........(Angle of
rectangle)
by pythagoras theorem
ac2 =ab2+bc2
. =121+3600
ac2 =3721
ac=√3721
ac=61
vishal7112003:
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Answered by
1
Answer:
Step-by-step explanation:
In triangle ABC
base=AB=11cm
HEIGHT=BC=60
hypo AC= v(11sq+60sq)
=v(121+3600)
=v(3721)
=61cm
hope it help u
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