ABCD IS A rectangle and k,l,m,n are the midpoints of sides AB,BC ,CD AND OA RESPECTIVELEY .IF KN=3CMAND AB=5CM THEN FOND BD AND LM. WHAT KIND OF A QUADRILATERAL IS KLMN ?JUSTIFY YOUR ANSWER AND[ DRAW THE FIGURE ALSO]
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given that,
ABCD is a rectangle.
and k,l,m,n are midpoint s
so
KN = 3× 2.5
= 7.5
Hence, BD is 15 cm as KN is midpoint ( by midpoint s theorem)
and LM = 7.5
KLMN is a parallelogram
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