Question

ABCD is a rectangle and O is the midpoint of AD ,P and Q are points on AB and CD ,respectively.such that AP=1/4AB and DQ=1/4DC.The ratio of area of the rectangle ABCD to that of the triangle OPQ is

Answer 1

Answer:

8:1 ratio

Step-by-step explanation:

Let the length of rectangle be x and width be y

Then area of ABCD = l×b

= xy

Since AP = 1/4AB

Height of triangle OPQ = 1/4AB = y/4

Base of triangle = Width of rectangle

= x

Area of triangle = 1/2bh

= 1/2 × x × y/4

= x/2 × y/4

= xy /8

Ratio of areas = xy/ xy /8

= 8/1

= 8:1