Math, asked by devilstudy, 11 months ago

need answer for the value of sin18 sin42 sin79 cosec54 pls​

Answers

Answered by Anonymous
2

Answer:

sin18 sin(60-18) sin(60+18) cosec54

 \frac{1}{4} sin \: 54 \times  \frac{1}{sin54}

since sinx*sin(60-x)*sin(60+x) = 1/4 sinx

and cosec x = 1/sinx

= 1/4

hope it helps you.....!

sorry for the Delay in answering

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Answered by Anonymous
31

________________

You Should First Know

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1.  cosec(x)  \:  =  \frac{1}{ \sin(x) }  \\

2.  \sin(60)  \times  \sin(60 - 18)  \times  \sin(60 + 18)  =  \\   \frac{1}{4}  \sin(54)

\huge \red{ \boxed{ \bf{ \ulcorner{ \mid{ \overline{ \underline{ANSWER}}}}}\mid }}

 =  >  \sin(18)  \sin(42)  \sin(78) cosec(54) \\  =  >  \frac{1}{4}  \times  \sin(54)  \times cosec(54) \\  =  >  \frac{1}{4}  \times  \sin(54)  \times  \frac{1}{\sin(54) }  \\  =  >  \frac{1}{4}

Hope It Helps

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