Question

Abcd is a rectangle and o is the midpoint of ad pq r point on ab and cd so thet aq=1/4ab and dq=1/4dc prove area of rectangle abcd

Answer 1

Answer:

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Let the length of rectangle be x and width be y

Then area of ABCD = l×b

= xy

Since AP = 1/4AB

Height of triangle OPQ = 1/4AB = y/4

Base of triangle = Width of rectangle

= x

Area of triangle = 1/2bh

= 1/2 × x × y/4

= x/2 × y/4

= xy /8

Ratio of areas = xy/ xy /8

= 8/1

= 8:1

Answer 2

Answer:

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Step-by-step explanation:

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