ABCD is a rectangle and P,Q,R and S are mid points of the sides AB,BC,CD and DA respectively, show that the quadrilateral PQRS is a rhombus?
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Step-by-step explanation:
from the mid point theorem
we can say that SR||AC
SR =1/2*AC
same way RQ= 1/2*DB
SP =1/2*DB
PQ =1/2*AC
and ABCD is a rectangle so diagonals are equal
so all the sides are equal in
SR=RQ=PQ=SP
so if you draw lines RP and SQ are drawn then are parallel to BC and AB which are perpendicular
so diagonals are also interesting at 90
so PQRS is a rhombus
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here is ur answer mate.....
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