Math, asked by tamadavarunkumar, 10 months ago

ABCD is a rectangle and P Q R and S are midpoints of the sides AB,BC,CD and DA respectively .show that the PQRS is a rhombus ​

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Answered by Anonymous
6

Answer:

Refrence of Image is in the Diagram :

 {\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(8.6,3){\large{A}}\put(9,1.3){\mathsf{10 m}}\put(10,1.3){\mathsf{24 m}}\put(7.7,0.9){\large{B}}\put(11.1,0.9){\large{C}}\put(9.9,2.1){\large{O}}\put(8,1){\line(1,0){3}}\put(11,1){\line(1,2){1}}\put(9,3){\line(3,0){3}}\put(11,1){\line(-1,1){2}}\put(8,1){\line(2,1){4}}\put(8,1){\line(1,2){1}}\put(12.1,3){\large{D}}\end{picture}}

Rhombous ABCD with Diagonals AC

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