Question

Abcd is a rectangle. forces of 9n, 8n, 3n act along the lines dc, cb and ba, respectively, in the directions indicated by the order of the letters. then the resultant force is

Answer 1

Answer: The resultant force is 20 N.

Explanation:

Given that,

Force on DC = 9 N

Force on CB = 8 N

Force on BA = 3 N

Using vector triangle addition law,

In the triangle CBA

$\vec{CB} +\vec{BA} = \vec{CA}$

$\vec{CA} = 8+3$

$\vec{CA} = 11 N$

Now, in the triangle DCA

$\vec{DC}+\vec{CA} = \vec{DA}$

Where, $\vec{DA}$ is the resultant force

$\vec{DA} = 9+11$

$\vec{DA} = 20 N$

Hence, the resultant force is 20 N.

Answer 2

"From the figure it is clear that,

Force on DC = 9 N

Force on CB = 8 N

Force on BA = 3 N

By using the vector triangle addition law,

In the triangle CBA

Now, in the triangle DCA

Where, DA is the resultant force

Hence, the resultant force is 20 N.

The resultant force is actually the sum of the individual forces acting on the vector triangle."