Question

ABCD is a rectangle having a length of 40 cm and the breadth of 26 and P Q R and S are the midpoints of Ab BC CD and CD respectively what is the area of the shaded part

Answer 1

Answer:

Area of the rectangle ABCD=AB×BC

=30×25

Now, DS=  

2

AD

​

=  

2

25

​

=12.5 cm

DR=  

2

DC

​

=  

2

30

​

=15 cm

∴ Area of △DSR= Area of △RCQ= Area of △QBP= Area of △PAS=  

2

1

​

×DS×DR

=  

2

1

​

×12.5×15=93.75 cm  

2

 

So, area of shaded region

=750−4×93.75=375 cm  

2

.