Math, asked by Jehan26, 8 months ago

ABCD is a rectangle. If AB = x-y, BC = 12 cm, CD = 16 cm, AD = X+Y Then (x, y) is

Answers

Answered by divyanshparekh
0

Answer:

(14, -2)

Step-by-step explanation:

ABCD is a rectangle,

AB =CD (property of a rectangle, opposite sides are equal )

Therefore,

x-y=16 ----- equation 1

Also BC and AD are equal. (property of a rectangle, opposite sides are equal )

Therefore,

X+Y = 12 -----eq 2

Solving these equations we get,

X= 14, Y = -2

hence your answer is (14, -2)

Answered by Anonymous
0

Answer:

ABCD is a rectangle

Side AB= CD ( opposite sides of a rectangle are equal)

X - y = 16

X = 16 + y -----1

Side BC= AD

12 = X + Y

12 - Y = X -------2

equalising 1 and 2

16 + y = 12 - y

16 - 12 = (-y)(-y)

4 = (-2y)

4/(-2) = y

(-2) = y

12 = X - 2

12 + 2 = X

14 = X

hence , X = 14 , y =(-2)

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