Question

An object moving with a constant acceleration, covers 145 cm
and 185 cm, during its 6th and 10th second of motion respectively.
What distance would it cover in the 16th second?​

Answer 1

Explanation:

• let (a) be the acceleration of an object
• acceleration is constant of an object
• i.e. a= constant
• a= dv/dt = constant = k
• dv/dt = k
• dv = kdt

v = k( t"-t')