Question

ABCD is a rectangle in which a squre PBRQ is inscribed area of PBRQ is 64 square centimetre,CP=1cm,AR=4cm,then find the area of shaded region

Answer 1

Answer:

2. 70/3 cm²

Step-by-step explanation:

You can use Theils' theorem.

Answer 2

Answer:

Given that,

Area of square PBRQ=64cm²

a²=8²

→a=8

PB=RB=8cm

CB=CP+PB

1+8=9cm

AB=AR+RB

4+8=12cm

Area of rectangle=l×b

9×12=108cm²

Area of ∆ARS=1/2×base ×height

=1/2×4×4

=2×4=8cm²

Area of ∆CPT=1/2×1×1

=0.5cm²

CB–(CP+SR)

9-5=4cm²

Area of ∆QST=1/2×4×4

=2×4=8cm²

Area of shaded region = Area of rectangle ABCD-(area of ∆ARS+ Area of ∆CPT+area of ∆QST)

=108-(8+0.5+8)

=108-16.5

=91.5