ABCD is a rectangle in which AB=2AD. P and Q are mid points of AD and AB respectively. If BP and DQ intersect at R, then the ratio of the area of quad BRDC and area( triangle BAP) is
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f u take the longer side as 12x and the shorter side as 6x
Then u will get the areas of BRDC : BAP
as 48x^2 : 18x^2
= 8:3
please mark as brainliest answer
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