Question

ABCD is a rectangle in which ad=14 cm ab=30 cm find the X and Y value
X+Y
D _______________ C
| |
14cm | |X
| |
A |_______________| B
30CM

Answer 1

Given:
AB =30 cm, AD= 14 cm
In rectangle opposite sides are equal.
AB = CD & BC = AD
x+y = 30.................(1)
x - y = 14.................(2)
On Adding eq 1 & 2
x+y + x - y = 30 +14
2x = 44
x = 44/2
x = 22 cm
Put the value of x= 22 in eq 1
x + y = 30
22 + y = 30
y = 30 - 22
y = 8 cm

Hence, the value of x = 22 cm & y= 8 cm.
HOPE THIS WILL HELP YOU....

Answer 2

Solution :-

Please refer to the attachment for the diagram. 

As we know that opposite sides of a rectangle are equal.

Length of the given rectangle = 30 cm = (x + y) = AB = CD

Breadth of the given rectangle = 14 cm = (x - y) = BC = AD

⇒ (x + y) + (x - y) = 30 + 14

+ y and - y are cancelled.

⇒ 2x = 44

⇒ x = 44/2

⇒ x = 22 

Substituting the value of x = 22 

x + y = 30

⇒ 22 + y = 30

⇒ y = 30 - 22

⇒ y = 8 

So, value of x is 22 and y is 8

Answer.