ABCD is a rectangle in which length is double of its breadth. Two equilateral triangles are drawn one each in length and breadth. Find the ratio of their areas.
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According the question,we get Length= double of breadth, that means ,l=2b,let abcd be the rectangle.AB= CD=2b.AD=BC=b
equilateral triangles are drawn on l and b,for triangle drawn on l,
all sides=2b, for triangle drawn on b, all sides= b, we know that
equilateral triangles are similar
therefore ratio of area of triangles = square of ratio of sides=2b/b, the whole square= 4/1, therefore the ratio is 4:1.
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