Question

ABCD is a rectangle inscribed in a circle. If AB = 16 cm, BC = 12 cm, find the radius and the area of the circle. (Take π = 3.14).

Answer 1

hi
here is your answer
see
if a rectangle is divided into 2 right angled triangles
then both of there base angles will be 16cm and 12cm
now using the Pythagorean theorem the hypotenuse or the diagonal of the rectangle can be found
${ab}^{2} + {bc}^{2} = {ac}^{2}$
(12^2)+(16^2)=(ac^2)
144+256=(ac^2)
400=ac^2
ac=√400
ac=20cm
now here the diagonal of the rectangle and the diameter of the circle is found
so radius= 20/2
10cm is the radius
area= πr^2
area=π(10^2)
area= 3.14×100
314cm^2
answer
radius=10cm
area=314cm^2

Answer 2

Hi....


Hope this helps..