Using Euclid’s division algorithm, find whether the pair of numbers 847, 2160
are co-primes or not.
Answers
Answered by
38
= > 2160 > 847.
(1 )
2160 = 847 * 2 + 466
Here remainder not equal to 0. Therefore Apply division to 847 and 466.
(2)
847 = 466 * 1 + 381
Here remainder not equal to 0. Therefore Apply division to 466 and 381
(3)
466 = 381 * 1 + 85
Here remainder not equal to 0. Therefore Apply division to 381 and 85.
(4)
85 = 41 * 2 + 3
Here remainder is not equal to 0.Therefore Apply division to 41 and 3.
(5)
41 = 3 * 13 + 2
Here remainder is not equal to 0. Therefore Apply division to 3 and 2.
(6)
3 = 2 * 1 + 1.
Here remainder is not equal to 0.Therefore Apply division to 3 and 2.
(7)
2 = 1 * 2 + 0.
Therefore the HCF of 847,2160 = 1.
Therefore the numbers are co-primes.
Hope this helps!
(1 )
2160 = 847 * 2 + 466
Here remainder not equal to 0. Therefore Apply division to 847 and 466.
(2)
847 = 466 * 1 + 381
Here remainder not equal to 0. Therefore Apply division to 466 and 381
(3)
466 = 381 * 1 + 85
Here remainder not equal to 0. Therefore Apply division to 381 and 85.
(4)
85 = 41 * 2 + 3
Here remainder is not equal to 0.Therefore Apply division to 41 and 3.
(5)
41 = 3 * 13 + 2
Here remainder is not equal to 0. Therefore Apply division to 3 and 2.
(6)
3 = 2 * 1 + 1.
Here remainder is not equal to 0.Therefore Apply division to 3 and 2.
(7)
2 = 1 * 2 + 0.
Therefore the HCF of 847,2160 = 1.
Therefore the numbers are co-primes.
Hope this helps!
SINGHisKING11:
yaa
Answered by
21
Answer:
'' Yes, the H.C.F OF (847,2160) IS CO-PRIME NUMBER''
Step-by-step explanation:
By using EUCLID division LEMMA
' find H.C.F OF 2160 and 847'
=》Since ,2160>847
so, let a=2160 ,b= 847
STEP 1: 2160 = 847×2+466
STEP 2: 847 = 466×1+381
STEP 3: 466 = 381×1+85
STEP 4: 381= 85×4+41
STEP 5: 85=41×2+3
STEP 6: 41=3×13+2
STEP 7: 3=2×1+1
STEP 8: 2=1×2+0
SO,THE REMAINDER IS NOW BECOME' 0'
AND THE HCFOF(2160,847) which is 1.
1 is a co-prime number
❤THANK YOU ❤
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