Question

ABCD is a rectangle, LB Perpendicular AC and MD perpendicular. prove that

1) triangle AMD congruent triangle CLB

2) LB = MD​

Answer 1

proof:In triangles AMD and CLB,we have

L AMD=L CLB=90'

L MAD=L LCM (alt.int.Ls)

AD=BC (opp.sides of rectangle)

therefore, by AAS congruence rule

triangles AMD =CLB

therefore by CPCT

LB=MD proved

Answer 2

Step-by-step explanation:

Sol: In a triangles BMC and DNA BC = DA (Opposite sides) ∠BCM = ∠DAN (alternate angles) ∠DNA = ∠BMC = 90° [DN and BM are perpendicular to AC] By AAS Congruency criterion ΔBMC ≅ ΔDNA DM = DN (CPCT).