ABCD is a rectangle .length AB=3X+2units. Breath BC=y-2,CD=x+10,DA=3y-10 then find the length of the diagonal.
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As ABCD is a Rectangle,
length = AB = CD
Breadth = BC = DA
_____________________
Length,
AB = CD
3x + 2 = x + 10
3x -x = 10 -2
2x = 8
x =8/2
x = 4
__________________
Breadth,
BC = DA
y-2 = 3y -10
-2 + 10 = 3y - y
8 = 2y
8/2 = y
4 = y
_______________
length = 3x + 2
= 3(4) + 2
= 12+ 2
= 14 units
breadth = y - 2
= 4 - 2
= 2 units
Now,
By Pythagoras Theorem,
Length² + breadth² = Diagonal²
14² + 2² = Diagonal²
196 + 4 = Diagonal²
200 = Diagonal²
√200 = Diagonal
10√2 units= Diagonal
i hope this will help you
-by ABHAY
length = AB = CD
Breadth = BC = DA
_____________________
Length,
AB = CD
3x + 2 = x + 10
3x -x = 10 -2
2x = 8
x =8/2
x = 4
__________________
Breadth,
BC = DA
y-2 = 3y -10
-2 + 10 = 3y - y
8 = 2y
8/2 = y
4 = y
_______________
length = 3x + 2
= 3(4) + 2
= 12+ 2
= 14 units
breadth = y - 2
= 4 - 2
= 2 units
Now,
By Pythagoras Theorem,
Length² + breadth² = Diagonal²
14² + 2² = Diagonal²
196 + 4 = Diagonal²
200 = Diagonal²
√200 = Diagonal
10√2 units= Diagonal
i hope this will help you
-by ABHAY
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