ABCD is a rectangle. Semicircles are drawn on AB and CD. l(AB) = 7 cm, 1(AD) = 10 cm. Find the area of the figure.
(1) 224 cm2 (2) 108.5 cm2 (3) 130.2 cm2 (4) 147 cm2
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Answer:
(option 1) 224 cm²
Step-by-step explanation:
area of the figure = (area of semicircle × 2) + (area of rectangle)
area of semicircle = 1/2 πr²
r = AB = 7cm
1/2 πr²
= 1/2 × π × 7²
= 76.69 cm²
area of rectangle = L×B
L = AD = 10cm
B = AB = 7cm
L×B = 10×7 = 70 cm²
area of the figure = (area of semicircle × 2) + (area of rectangle)
= ( 76.69 × 2) + ( 70 )
= 153.38 + 70
= 223.38 ~ 224 cm²
area of the figure is 224 cm²
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