Question

ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB =46 °, find ∠OBC

Answer 1

EACH AND EVERY ANGLES IN A RECTANGLE IS EQUAL TO 90°.

DIAGONALS OF RECTANGLE CUTS EACH OTHER INTO THEIR HALF.

SO,

AO = BO.

WE KNOW THAT,

ANGLES OPPOSITE TO EQUAL SIDES ARE ALSO EQUALS.

SO,

<OBA = <OAB

<OBA = 46° ___ (1)

WE KNOW,

<ABC = <OBA + <OBC

90° = <46° + <OBC

<OBC = 44°.

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