ABCD is a Rectangle whose Diagonals AC and BD intersect at O, If Angle OAB = 32°, Find Angle ABC and OBC
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2
Answer:
R.E.F image
∠CAB=∠DCA (alternate)
=27
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and ∠ACB=90
∘
−27
∘
=63
∘
∠CBO=90
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∴∠CBO=90−63=27
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Answered by
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Answer:
thanks for following thanks
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