ABCD is a rectangle whose diagonals AC and BD intersect atO if angle OAB is equal to 46 degree find angle OBC
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Triangle OAB is isosceles with OA = OB
Therefore angle OBA = 28 degrees
angle OBC = 90 - angle OBA = 90 - 28 = 62 degrees
Hope you got it!
~Saumya Kawalia
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angle OBC=134'
done we get it
done we get it
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