Question

ABCD is a rectangle whose diagonals AC and BD meet at O.Given that the angke CAB=28 degree,find the angles AOB and ADB

Answer 1

Step-by-step explanation:

Given :- angle CAB=28degree

Angle of a rectangle is right angle =90degree

Angle ABC =angle ABO+angle OBC

90 degree= x + x

90degree= 2x

45degree=x

AngleABO =45degree

Angle OBC=45degree

In triangle AOB

Angle ABO+ angle AOB+angle OAB =180degree

45degree+angle AOB +28 degree=180degree

73degree+angle AOB=180degree

Angle AOB=180-73 degree

Angle AOB=107degree

AngleADB+ Angle BDC=90degree

x + x =90 degree

2x =90degree

x =45 degree

Therefore angle ADB =45 degree