Abcd is a rectangle whose three vertices are B (4,0) C (4,3)d (0,3)find the length of one of its diagonal
Answers
Answered by
171
Hi !
ABCD is a rectangle.
BD is the diagonal
B = (4,0)
D = (0,3)
BD = [tex] \sqrt{ (x_{2} + x_{1} ) ^{2} + \sqrt{ (y_{2} - y_{1} ) ^{2} } \\ \\ \\ \sqrt{ (4 - 0 ) ^{2} + \sqrt{ (0- 3 ) ^{2} } [/tex]
= √(16 + 9)
= √25
BD = 5 units
Length of diagonal = BD = 5 units
ABCD is a rectangle.
BD is the diagonal
B = (4,0)
D = (0,3)
BD = [tex] \sqrt{ (x_{2} + x_{1} ) ^{2} + \sqrt{ (y_{2} - y_{1} ) ^{2} } \\ \\ \\ \sqrt{ (4 - 0 ) ^{2} + \sqrt{ (0- 3 ) ^{2} } [/tex]
= √(16 + 9)
= √25
BD = 5 units
Length of diagonal = BD = 5 units
Answered by
37
Answer:
Step-by-step explanation:
Hi !
ABCD is a rectangle.
BD is the diagonal
B = (4,0)
D = (0,3)
BD = \sqrt{ (x_{2} + x_{1} ) ^{2} + \sqrt{ (y_{2} - y_{1} ) ^{2} } \\ \\ \\ \sqrt{ (4 - 0 ) ^{2} + \sqrt{ (0- 3 ) ^{2} }
= √(16 + 9)
= √25
BD = 5 units
Length of diagonal = BD = 5 units
Similar questions