Question

ABCD is a rectangle with AB ,equal 12cm and BC equal to 5cm , find AC

Answer 1

As we know all angles of rectangles measure 90°

So,

Given , AB = 12cm

BC = 5cm

BC is the diagonal and it divides the rectangle in two triangles - 1

from 1 we get to know

angle A = 90°

and the side in front of angle A is called hypotenuse

As we know the formula

H^2 = square of base+square of height

5^2 = 12^2 + B^2

25 = 144 + B^2

B^2 = 144-25

Answer 2

Step-by-step explanation:

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