Find the smallest number which when divided bye bhai 35 ,56 and 105 leave a reminder of 6 in each case.
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Answer:
845 is the smallest number which when divided by 35, 56 & 105 , leaves a remainder of 5 in each case.
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Step-by-step explanation:
LCM for 35= 5×7
LCM for 56=8×7
LCM for 105=5×3×7
LCM for all numbers = 5×3×7×8
=15×56
=790
the smallest number= 790-6=784
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