Math, asked by Ritesshh7854, 9 months ago

Find the smallest number which when divided bye bhai 35 ,56 and 105 leave a reminder of 6 in each case.

Answers

Answered by ArabNibs
0

Answer:

845 is the smallest number which when divided by 35, 56 & 105 , leaves a remainder of 5 in each case.

Answered by calmgroup
3

Step-by-step explanation:

LCM for 35= 5×7

LCM for 56=8×7

LCM for 105=5×3×7

LCM for all numbers = 5×3×7×8

=15×56

=790

the smallest number= 790-6=784

Similar questions