ABCD is a rectangle with angle bac equal to 128 find angle DCB
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in angle DBC
Angle BAC=angle BDC
As angle BDC =32
The sum of interior angles of triangle =180
angle BDC+Angle C+Angle B=180
32+90+angle DBC =180
Angle DBC=58
Angle BAC=angle BDC
As angle BDC =32
The sum of interior angles of triangle =180
angle BDC+Angle C+Angle B=180
32+90+angle DBC =180
Angle DBC=58
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