Question

Abcd is a rectangle with ∟bac = 480 . Then ∟dbc is equal to :

Answer 1

Hey mate!
Here is your answer > >

Given-ABCD is a rectangle ,<angle BAC=48°

To find-<DBC

Proof-In rectangle ABCD

AC=DB (Digonals of a recatngle are equal)

1/2AC=1/DB

AO=BO

In triangle AOB

AO= BO (Proved above)

So, <OAB=<OBA=48 (Angles opposite to equal sides of a triangle are equal)

Now Angles of a rectangle are of 90°

So, <CBA=<OBA+<CBD
90 =48+<CBD
<CBD=42°

Hope it helps!

Thankyou ☆ ☆

Answer 2

Answer:

42 degree

Step-by-step explanation:

Given-ABCD is a rectangle ,<angle BAC=48°

To find-<DBC

Proof-In rectangle ABCD

AC=DB (Digonals of a recatngle are equal)

1/2AC=1/DB

AO=BO

In triangle AOB

AO= BO (Proved above)

So, <OAB=<OBA=48 (Angles opposite to equal sides of a triangle are equal)

Now Angles of a rectangle are of 90°

So, <CBA=<OBA+<CBD

90 =48+<CBD

<CBD=42°