Question

ABCD is a rectangle with dimensions 24m by 16m.AFE is a triangle such that EF⊥ADandEF = 10m. Calculate the area of the shaded portion.

Answer 1

Step-by-step explanation:

GIVEN,

DC = AB = 24m

AD = BC = 16m

EF = 10m

area of the shaded region = area of ABCD - area of ∆AFD

area of ABCD

= 16 × 24

= 384 m^2

area of ∆ AFD

= 1/2 × 10 × 16

= 80m^2

area of shaded region

= 384-80

= 304m^2

Answer 2

Answer:

304m^2

Step-by-step explanation:

DC = AB = 24m

AD = BC = 16m

EF = 10m

area of the shaded region = area of ABCD - area of ∆AFD

area of ABCD

= 16 × 24

= 384 m^2

area of ∆ AFD

= 1/2 × 10 × 16

= 80m^2

area of shaded region

= 384-80

= 304m^2

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