Math, asked by angelbenjamin39208, 1 year ago

ABCD is a rectangle with O as any point in its interior.If area of triangle AOD= 3cm square and area of triangle BOC= 6cm square,then what is the area of rectangle ABCD?

Answers

Answered by 6Shivam92
54
given: ABCD is a rectangle, and O is any point in its interior.

area(ΔAOD)= 3 sqcm  and area(ΔBOC)=6 sq cm.

from O draw a line EF parallel to AB intersecting AD at E and BC at F.

therefore OE⊥AD and OF⊥BC.

let OE=x and OF=y

OE+OF=EF=AB

therefore x+y=AB......(1)

area(ΔAOD)+area(ΔBOC)=3+6=9 sq cm.

since BC=AD [opposite sides of a rectangle]

since EF=AB

AD*AB=18

area of the rectangle ABCD = AB*AD=18

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Answered by ishitamukherjee1204
7

Answer:

18cm^2

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