Question

ABCD is a rectangle with sides 18 cm and 12 cm as shown in the figure. EDC idle triangle inside the rectangle. Calculate the area of the shaded portion. FIGURE IS GIVEN DON'T GIVE ANY EXCUSE. ​

Answer 1

The area of the shaded portion, if the rectangle measures 18 cm x 12 cm and a triangle EDC is present inside the rectangle, is 108 cm².

Step-by-step explanation:

Step 1:

Length of the rectangle, CD = 18 cm

Breadth of the rectangle, BC = 12 cm

∴ Area of the rectangle ABCD = length * breadth = 18 * 12 = 216 cm²

Step 2:

Base of the ΔEDC, CD = 18 cm

Height of the ΔEDC = BC = 12 cm

∴  Area of the Δ EDC = $\frac{1}{2}$ * base * height = $\frac{1}{2}$ * 18 * 12 = 108 cm²

Step 3:

Thus,

The area of the shaded portion is given by,

= [Area of the rectangle ABCD] - [Area of the Δ EDC]

= 216 cm² - 108 cm²

= 108 cm²

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Answer 2

Step-by-step explanation:

Step 1:

Length of the rectangle, CD = 18 cm

Breadth of the rectangle, BC = 12 cm

∴ Area of the rectangle ABCD = length * breadth = 18 * 12 = 216 cm²

Step 2:

Base of the ΔEDC, CD = 18 cm

Height of the ΔEDC = BC = 12 cm

∴ Area of the Δ EDC = \frac{1}{2}

2

1

* base * height = \frac{1}{2}

2

1

* 18 * 12 = 108 cm²

Step 3:

Thus,

The area of the shaded portion is given by,

= [Area of the rectangle ABCD] - [Area of the Δ EDC]

= 216 cm² - 108 cm²

= 108 cm²

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