ABCD is a rhombous. if AC =8cm DB =6 cm, find the lengh of BC
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ABCD is a rhombus [draw a figure]
AC and DB are two diagonals.
diagonals bisect perpendicularly each other in rhombus
intersecting point is " O"
AO = AC/2 = 8/2 =4 cm
OD = DB/2 = 6/2 =3 cm
AOD is a right angled triangle <AOD =90
AD^2 = (AO)^2 +(OD)^2
= 4^2 +3^2
=16+9
=25
therefore
AD = 5 cm
in rhombus all side are equal in length
AB=BC=CD=DA= 5 cm
AC and DB are two diagonals.
diagonals bisect perpendicularly each other in rhombus
intersecting point is " O"
AO = AC/2 = 8/2 =4 cm
OD = DB/2 = 6/2 =3 cm
AOD is a right angled triangle <AOD =90
AD^2 = (AO)^2 +(OD)^2
= 4^2 +3^2
=16+9
=25
therefore
AD = 5 cm
in rhombus all side are equal in length
AB=BC=CD=DA= 5 cm
mahimishra:
THANKS EVERY MUCH SIR
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