Question

ABCD is a rhombus AC equal to 12 centimetre BD equal to 16 cm find the area of quadrilateral by joining the midpoints of sides of rhombus ABCD

Answer 1

Hi ,

ABCD is a Rhombus ,

Let d1 = AC = 12 cm ,

d2 = BD = 16 cm

Area of the Rhombus = ( d1 × d2 )/2

A = ( 12 × 16 )/2

A = 96 cm² ---( 1 )

Now ,

area of the

quadrilateral = ( area of ABCD )/2

= 96/2

= 48 cm²

I hope this helps you.

: )