Question

weight of a body decreases by 1.5%, when it is raised to a height h above the surface of earth. when the same body is taken to same depth h in a mine, its weight will show

Answer 1

Weight= mg
As mass everywhere remains same, so there will be change in the value of g.
g'= g - 1.5%g = 98.5/100g
For height
g'= g(1-2h/R)
98.5/100g = g(R-2h)/R
98.5R = 100R - 200h
h = (1.5/200)R = 0.0075R
For depth
g'= g(1-d/R). [d=h=0.0075R]
g'= g(1-0.0075)
g'= 10 * 0.9925. [g=10]
g'= 9.9

%change = (∆g/g) *100
∆g= 10- 9.925= 0.075
℅ = (0.075/10)*100
=0.75℅

HOPE THIS WAS HELPFUL

Answer 2

the weight will show 0.75% decrease