Question

ABCD is a rhombus, EABF is a straight line such that EA=AB=BF. Prove that ED and FC when produced meet at right angles.

Answer 1

Answer:

ABCD is a rhombus, EABF is a straight line such that EA = AB = BF. Prove that ED. and FC when produced meet at right angles. We know that the diagonals of a rhombus are perpendicular bisector of each other.

Answer 2

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♡We know that the diagonals of a rhombus are perpendicular bisector to each other.