ABCD is a rhombus. Find the value of x and y
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Answer:
.......the value of x is 62° ( alt. int. angles)
the value of y is" i dont know srry"
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Opposite angles of a rhombus are equal
So angleA = angleC
62* = angleC
angleOAB = 62/2 = 31*
By the transversal line CA,
angleOAB = angleOCD
31* = x* {substitute with the diagram..
angleOCB = 31*
In triangle OBC,
angleCOB + angleOBC + angleOCB = 180*
90 + y + 31 = 180*
y + 121 = 180
y = 180 - 121
y = 59*
Thus, x = 31* and y = 59*
( * here indicates degree symbol i.e, I have used for my convenience. )
Hope, you understood my explanation.. and helped you...
So angleA = angleC
62* = angleC
angleOAB = 62/2 = 31*
By the transversal line CA,
angleOAB = angleOCD
31* = x* {substitute with the diagram..
angleOCB = 31*
In triangle OBC,
angleCOB + angleOBC + angleOCB = 180*
90 + y + 31 = 180*
y + 121 = 180
y = 180 - 121
y = 59*
Thus, x = 31* and y = 59*
( * here indicates degree symbol i.e, I have used for my convenience. )
Hope, you understood my explanation.. and helped you...
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