Question

ABCD is a rhombus. If ∠ACB=40°. find ∠ADB​

Answer 1

Answer:

In given figure ABCD is a rhombus. We know that diagonals of rhombus bisect each other perpendicularly.

Hence, ∠BOC= 90

∘

∠OCB = 40

∘

(Given)

AD∥BC and BD is the transversal --- (Opposite sides of rhombus are parallel to each other)

∴ ∠ADB = ∠DBC ---- (Alternate angles)

In △OBC,

∠BOC + ∠OCB + ∠OBC = 180

∘

⇒ 90

∘

+ 40

∘

+ ∠OBC = 180

∘

⇒ ∠OBC =180

∘

- 130

∘

∴ ∠OBC = 50

∘

But ∠OBC =∠DBC

∴ ∠ADB = 50

∘

---( Alternate angle)

Answer 2

Answer:50°

Step-by-step explanation: