Math, asked by Javeriarafi, 1 year ago

ABCD is a rhombus if angle BAC =38 degree find angle ACB ,angle DAC and angle ADC

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Answered by AshmitJain3107
202
Given that ABCD is a rhombus with diagonal AC and <CAD = 38°.
We need to find :-
(1) <ACB
As we know that in a rhombus opposite angles are equal
=> <DAB = <DCB
Also the diagonal of a rhombus bisects the angles .
So , <DAC = <CAB = 38°.
=> <ACB = <DAC = 38°. (alternate angles)
(2) <DAC
As proved above that <DAC = <CAB = 38°.
(3) <ADC
As said above that in a rhombus opposite angles are equal .
So <CBA = <ADC
We know that <DAC + <CAB = <DAB
= 38° + 38° = 76°.
As AB || CD and AD and BC are transversal,
<DAB + <CBA = 180° ( co-interior angles)
= 76° + <CBA = 180°
= <CBA = 180° - 76°
=> <CBA = 104°.
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Answered by shanenasl8437
20

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