ABCD is a rhombus if BCA 50 find angle adc
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Diagonals of a rhombus are angular bisector of the interior angles at it's vertices.
Therefore, BCA + DCA = BCD = 2×50° = 100°.
Now, adjacent interior angles are supplementary angles.
Therefore, BCD + ADC = 180°.
ADC = 180° - 100° = 80°.
Therefore, BCA + DCA = BCD = 2×50° = 100°.
Now, adjacent interior angles are supplementary angles.
Therefore, BCD + ADC = 180°.
ADC = 180° - 100° = 80°.
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Answer:
Diagonals of a rhombus are angular bisector of the interior angles at it's vertices. Therefore, BCA + DCA = BCD = 2×50° = 100°. Now, adjacent interior angles are supplementary angles. Therefore, BCD + ADC = 180°.
Step-by-step explanation:
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