ABCD is a rhombus in which angle CDB IS 55 degrees then find the angle A
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Answer:
Solution:
Given that ABCD is a rhombus and DAB =
70
Since, ABCD is a rhombus so
ABC L CDA
and 2 DCB = 2 DAB = 70°.. 1)
And we know that,
DAB+L ABC + L DCB +4 CDA 360
70°+ L ABC +70° +2 CDA = 360°
L ABC+ L CDA+ 140° 360
L ABC+L CDA = 360° - 1400°
L ABC + 2 CDA = 220
Since, 2 ABC = 2 CDA
So, 4 ABC +2 ABC 220°
24 ABC = 220°
L ABC = 110°
Thus,
CDB 1/2(4 ABC)
= 1/2(110)
L CDB =55
Answer.
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