Question

ABCD is a rhombus in which diagonal AC bisects diagonal BD at ‘O’ such that
AO = 3cm , BO = 4cm. Find the measure of each side. pls show working

Answer 1

Using Pythagoras theorem

Side² = hypotenuse
AO and BO are sides

Since diagonal of a rhombus bisect at 90° we can apply Pythagoras theorem


Hence,
3² + 4² = side²

=> 9 + 16 = side²
=> side² = 25
=> side = √25
side = 5cm


Since all sides of a rhombus are equal we can say
Each side is of 5cm



Hope it helps dear friend ☺️✌️