Question

ABCD is a rhombus one of the diagonal is 24 cm find other diagonal

LENGTH=2Y+3
BREADTH=3Y-2

Answer 1

2y+3=3y-2
y=5
5= ( sqrt( 24×24 +sqr ×))÷2
100= 576 + sqrx
x=21.84

Answer 2

Given that One of its diagonal = 24 cm.

We know that Diagonals of a rhombus bisect each other.

= > 2y + 3 = 3y - 2

= > 2y - 3y = -2 - 3

= > -y = -5

= > y = 5.

Substitute y = 5 in above, we get

= > Length = 2(5) + 3 = 13.

= > Breadth = 3(5) - 2 = 13.

We know that By Pythagoras theorem

= > (13)^2 = (7.5)^2 + x^2

= > 169 = 56.25 + x^2

= > 112.75 = x^2

= > x = 10.6cm.

Hence, the length of another diagonal = 2 *  10.6 = 21.2 cm.

Hope it helps!