ABCD is a rhombus. Prove that AB square +BCsquare+CDsquare+DAsquare=ACsquare+BDsquare.. Are there any other process of doing this unlike the process I have posted..
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No... I couldn't find! This one is very easy. Well initially I have also problems. But remember one thing in a rhombus diagonals are perpendicular bisector.
It means all angles of diagonal formed on their meeting point will be 90 degree. And if AB and DC are diagonals meeting at O then, AO=BO and CO =DO.
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