Question

ABCD is a Rhombus prove that AC^2+BD^2=4AB^2

Answer 1

property for rhombus is diagonals bisect each other and diagonals are perpendicular to each other.
by using this we can understand that diagonals meting point is exactly at midpoint
and it divides rhombus into 4 equal triangles. therefore we can say that Ac^2+BD^2=4AB^2