Question

ABCD is a rhombus seg BD is
the diagonale. If
angle ABD = 32°
then find angle DBC.

​

Answer 1

Answer:

Draw the picture. I'm not smart enough to do it without being able to look at it.

If angle AOB = 70, the opposite angle, DOC, is also 70. These two angles total 140, so the othe two central angles, BOC and AOD, total 220 (360 - 140), and each one = 110. Since angle DAC = 32, angle ACB also = 32. All the interior angles of a triangle = 180. Adding the two known angles (BOC = 110, OCB = 32) = 142. Subtracting 142 from 180 = 32.

Angle DBC = 32.

As I write this the Big 10 is 6 and 0. Go Wisconsin!

Step-by-step explanation:

Draw the picture. I'm not smart enough to do it without being able to look at it.

If angle AOB = 70, the opposite angle, DOC, is also 70. These two angles total 140, so the othe two central angles, BOC and AOD, total 220 (360 - 140), and each one = 110. Since angle DAC = 32, angle ACB also = 32. All the interior angles of a triangle = 180. Adding the two known angles (BOC = 110, OCB = 32) = 142. Subtracting 142 from 180 = 32.

Angle DBC = 32.

As I write this the Big 10 is 6 and 0. Go Wisconsin!

make me brainlist please मै तुम्हारे पैर पढ़ती हूं

please tumko meri or mere bf ki duan lage

pagl आउरत तुझे ये question nahi अता

ghadi