abcd is a rhombus show that diagonal ac bisects angle a as well as angle c and diagonal bd bisects angle b as well as angle d
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In triangle AOB and AOD,
AB = AD {SIDES OF ROHMBUS}
AO = AO
BO= BO
∆AOB congruent ∆AOD
angle BAO = angle DAO
similarly, angle BCO = angle DCO
You can show the other two in the same way by congruenting ∆BOC and ∆BOA☺️
AB = AD {SIDES OF ROHMBUS}
AO = AO
BO= BO
∆AOB congruent ∆AOD
angle BAO = angle DAO
similarly, angle BCO = angle DCO
You can show the other two in the same way by congruenting ∆BOC and ∆BOA☺️
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gokul87:
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