Question

abcd is a rhombus such that angle acb=40 find angle adb

Answer 1

Answer:

50°

Step-by-step explanation:

Given:

ABCD is a Rhombus

Angle ACB=40

To Find:

Angle ADB

solution:

Diagonal BD and AC bisect each other at 90°( as diagonals of rhombus bisect each another

Angle BOC=90°

In ∆BOC,

angle BOC+Angle CBD+angle ACB=180°

90°+angle CBD+40°=180°

angle CBD=180°–130°

angle CBD=50°

in ∆BOC,∆AOD

SIDE AD=BC(ALL SIDES ARE EQUAL IN A RHOMBUS)

OB=OD[DIAGONALS BISECT EACH OTHER]

AO=OC[ " " " " ]

BY SAS

∆BOC=~∆AOD