Question

ABCD is a rhombus such that angle ACB = 40° . Then angle ADB = ?

Answer 1

Given that, ABCD is a rhombus

two diagonals are bisect each other
there fore, angle of BOC is 90°

from this above question angle of OCB is 40°

AD||BC

angle of ADB=angle of DBC( alternate angles)..................................(1)

<OBC+ <BOC+ <OCB=180°

Let <OBC is equal to x, then

x+90°+40°=180( we know that in a triangle the sum of the three angles is equal to 180°)

so,

x+130=180

x=180-130

x=50

x= <BOC

but in equation (1)

<BOC=. <ADB=50°

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Answer 2

Here is the answer...

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